IPMAT IndoreAlgebra > Easy{1}\{1\}{1}{1,−1}\{1,-1\}{1,−1}{1,0}\{1,0\}{1,0}{1,0,−1}\{1,0,-1\}{1,0,−1}✅ Correct Option: 2Related questions:IPMAT Indore 2024Let fff and ggg be two functions defined by f(x)=∣x+∣x∣∣f(x) = |x + |x||f(x)=∣x+∣x∣∣ and g(x)=1xg(x) = \frac{1}{x}g(x)=x1 for x≠0x \neq 0x=0. If f(a)+g(f(a))=136f(a) + g(f(a)) = \frac{13}{6}f(a)+g(f(a))=613 for some real aaa, then the maximum possible value off(g(a)) f(g(a))f(g(a)) is:IPMAT Indore 2020Given f(x)=x2+log3xf(x) = x^2 + \log_3 xf(x)=x2+log3x and g(y)=2y+f(y)g(y) = 2y + f(y)g(y)=2y+f(y), then the value of g(3)g(3)g(3) equalsIPMAT Indore 2022If f(x2+f(y))=xf(x)+yf\left(x^{2}+f(y)\right)=x f(x)+yf(x2+f(y))=xf(x)+y for all non-negative integers xxx and yyy, then the value of [f(0)]2+f(0)[f(0)]^{2}+f(0)[f(0)]2+f(0) equals _________.