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We have a bag of tokens. Each token has a label mm chosen from the squares of the first nn natural numbers, with frequency m\sqrt{m}. What is the arithmetic mean of the labels?

Solution

✅ Correct Option: 1

The tokens have labels from the squares of the first nn natural numbers: 12,22,32,…,n21^2, 2^2, 3^2, \ldots, n^2.

Each label mm appears with frequency m\sqrt{m}:

  • Label 12=11^2 = 1 appears 1=1\sqrt{1} = 1 time
  • Label 22=42^2 = 4 appears 4=2\sqrt{4} = 2 times
  • Label 32=93^2 = 9 appears 9=3\sqrt{9} = 3 times
  • Label k2k^2 appears k2=k\sqrt{k^2} = k times
  • Label n2n^2 appears n2=n\sqrt{n^2} = n times

The total number of tokens is:

Total tokens=1+2+3+⋯+n\text{Total tokens} = 1 + 2 + 3 + \cdots + n

=∑k=1nk= \sum_{k=1}^{n} k

=n(n+1)2= \frac{n(n+1)}{2}


The sum of all label values is:

Sum=12⋅1+22⋅2+32⋅3+⋯+n2⋅n\text{Sum} = 1^2 \cdot 1 + 2^2 \cdot 2 + 3^2 \cdot 3 + \cdots + n^2 \cdot n

=∑k=1nk2⋅k= \sum_{k=1}^{n} k^2 \cdot k

=∑k=1nk3= \sum_{k=1}^{n} k^3

=(n(n+1)2)2= \left(\frac{n(n+1)}{2}\right)^2


The arithmetic mean of the labels is:

Mean=Sum of all label valuesTotal number of tokens\text{Mean} = \frac{\text{Sum of all label values}}{\text{Total number of tokens}}

=(n(n+1)2)2n(n+1)2= \frac{\left(\frac{n(n+1)}{2}\right)^2}{\frac{n(n+1)}{2}}

=n(n+1)2= \frac{n(n+1)}{2}

Therefore, the arithmetic mean of the labels is n(n+1)2\frac{n(n+1)}{2}.

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