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A shopkeeper marks the price of an item 50%50\% above its cost. During a festival, he offers a sequence of discounts — first a 20%20\% discount, then an additional 10%10\% off on the reduced price, and finally gives a further rebate of ₹30₹30 on the total bill for 10 identical items. If after all these reductions, he still makes a profit of 5%5\% on selling the 10 items, what is the cost price of one item?

Solution

✅ Correct Option: 2

Let the Cost Price (CP) of one item be xx.

Since there are 10 identical items:

Total Cost Price =10x= 10x

The Marked Price (MP) is 50%50\% above the CP.

MP of one item =x+50%= x + 50\% of xx

=1.5x= 1.5x

Total Marked Price (for 10 items) =10×1.5x= 10 \times 1.5x

=15x= 15x


Applying the first discount of 20%20\%:

Price after first discount =15x×(1−20100)= 15x \times (1 - \frac{20}{100})

=15x×0.8= 15x \times 0.8

=12x= 12x

Applying the second discount of 10%10\% on the reduced price:

Price after second discount =12x×(1−10100)= 12x \times (1 - \frac{10}{100})

=12x×0.9= 12x \times 0.9

=10.8x= 10.8x


After the rebate of ₹30₹30 on the total bill:

Final Selling Price (SP) =10.8x−30= 10.8x - 30


The shopkeeper makes a total profit of 5%5\% on the Total Cost Price (10x10x).

Final SP =Total CP+Profit= \text{Total CP} + \text{Profit}

=10x+(5%= 10x + (5\% of 10x)10x)

=10x+0.5x= 10x + 0.5x

=10.5x= 10.5x


Equating the two expressions for Final Selling Price:

10.8x−30=10.5x10.8x - 30 = 10.5x

10.8x−10.5x=3010.8x - 10.5x = 30

0.3x=300.3x = 30

x=300.3x = \frac{30}{0.3}

x=100x = 100

Therefore, the cost price of one item is ₹100₹100.

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