If 25% of the female students from institute V are transferred to institute Z and 20% of the male students from institute Z are transferred to institute W, then after the transfer, the percentage (up to two decimal places) by which the number of students in institute Z are more than that of the students in institute U is _____.

Total students $= 5500$, so $1\% = 55$ students.

Pie chart gives the total students (male + female) of each institute. Radar graph gives only the male students.

---

Totals before the transfer:

U $= 12 \times 55 = 660$

V $= 8 \times 55 = 440$

Z $= 20 \times 55 = 1100$

Males (radar graph): V $= 200$, Z $= 700$

---

Female students in V $= 440 - 200 = 240$

$25\%$ of them move into Z:

$\dfrac{25}{100} \times 240 = 60$ students join Z

---

$20\%$ of the male students of Z move out to W:

$\dfrac{20}{100} \times 700 = 140$ students leave Z

---

Students in Z after the transfer $= 1100 + 60 - 140$

$= 1020$

U is not part of any transfer, so it stays at $660$.

---

Percentage by which Z is more than U $= \dfrac{1020 - 660}{660} \times 100$

$= \dfrac{360}{660} \times 100$

$= 54.545\ldots\%$

$\approx 54.55\%$

Therefore, Z has $54.55\%$ more students than U.