Skip to main contentSkip to solution

Three of the numbers are alike in a certain way and one is different. Select the number that is different.

Solution

✅ Correct Option: 3

Factorise each: 133=7×19133 = 7 \times 19, 209=11×19209 = 11 \times 19, 247=13×19247 = 13 \times 19.

All three are multiples of 19. But 119=7×17119 = 7 \times 17, which has no factor of 19, so it is the odd one out.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question