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If the numbers from 1 to 49 which are exactly divisible by 3 are arranged in ascending order, the minimum number being on top, which would come in eighth place from the bottom?

Solution

✅ Correct Option: 2

Multiples of 3 up to 49 are 3, 6, ..., 48, which is 16 numbers.

Eighth from the bottom is the 16−8+1=916 - 8 + 1 = 9th from the top.

The 9th multiple of 3 is 3×9=273 \times 9 = 27.

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