CUET General Test 2026 14th May Shift 1 PYQs

The sum of digits of a two-digit number is 14 and the difference between the two digits of the number is 2. The product of the two digits of the number is:

If $2^{(x+y)} = 64$ and $128^{(x-y)} = 2$, then what is the value of x?

If 2x + 3y - 8 = 0 and 3x - 2y - 12 = 0, then $4x^2 + y^2 - 4x$ is equal to: