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Three solid cubes of sides 1 cm, 6 cm, and 8 cm are melted to form a new cube. The surface area of the cube so formed is:

Solution

✅ Correct Option: 3

Volume is conserved on melting: V=13+63+83=1+216+512=729 cm3V = 1^3 + 6^3 + 8^3 = 1 + 216 + 512 = 729\ cm^3.

Side of new cube: a=7293=9 cma = \sqrt[3]{729} = 9\ cm.

Surface area of a cube =6a2=6×81=486 cm2= 6a^2 = 6 \times 81 = 486\ cm^2.

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