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If the height of a pole is 232\sqrt{3} meters and the length of its shadow is 2 meters. The angle of elevation of the sun is:

Solution

✅ Correct Option: 3

tan⁡θ=heightshadow=232=3\tan\theta = \frac{\text{height}}{\text{shadow}} = \frac{2\sqrt{3}}{2} = \sqrt{3}.

θ=tan⁡−1(3)=60∘\theta = \tan^{-1}(\sqrt{3}) = 60^{\circ}.

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