Geometry

Triangles

Medium

A ladder is placed to reach a window 63 cm high. The ladder is then turned over to the opposite side of the street and is found to reach a point 56 cm high. If the ladder is 65 cm long, then the width of the street will be:

16 cm

33 cm

39 cm

49 cm

✅ Correct Option: 4

The ladder forms two right triangles with the same foot.

First base $= \sqrt{65^2 - 63^2} = \sqrt{4225 - 3969} = \sqrt{256} = 16$

Second base $= \sqrt{65^2 - 56^2} = \sqrt{4225 - 3136} = \sqrt{1089} = 33$

Width of street $= 16 + 33 = 49$ cm.

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A ladder is placed to reach a window 63 cm high. The ladder is then turned over to the opposite side of the street and is found to reach a point 56 cm high. If the ladder is 65 cm long, then the width of the street will be:

Solution

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