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A bag contains 4 white and 2 black balls. Another bag contains 3 white and 5 black balls. If one ball is drawn from each bag, find the probability that both balls are white.

Solution

✅ Correct Option: 4

The two draws are independent, so multiply the individual probabilities.

P(white from first bag) =4/6=2/3= 4/6 = 2/3

P(white from second bag) =3/8= 3/8

Required probability =(2/3)(3/8)=6/24=1/4= (2/3)(3/8) = 6/24 = 1/4.

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