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A man is watching from the top of a tower a boat speeding away from the tower. The boat makes an angle of depression of 60° with the man's eye when at a distance of 60 metres from the tower. After 9 seconds, the angle of depression becomes 30°. The speed of the boat, assuming that it is running in still water, will be:

Solution

✅ Correct Option: 3

A man at the top of a tower watches a boat speeding away. Initially, the boat is at a distance of 60 metres from the tower and makes an angle of depression of 60° with the man's eye. After 9 seconds, the angle of depression becomes 30°.

What we need to find: The speed of the boat

Understanding the setup: Imagine you're standing on top of a tower looking down at a boat. The boat is moving away from the tower in a straight line. "Angle of depression" is the angle you look downward from horizontal to see the boat.


When the boat is at the first position (60 m from the tower), the angle of depression is 60°60°.

In a right triangle, tan⁡(angle)=oppositeadjacent=heightdistance\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}} = \frac{\text{height}}{\text{distance}}

tan⁡(60°)=h60\tan(60°) = \frac{h}{60}

Since tan⁡(60°)=3\tan(60°) = \sqrt{3} (standard value to memorize):

3=h60\sqrt{3} = \frac{h}{60}

h=603h = 60\sqrt{3} metres


After 9 seconds, the angle of depression becomes 30°30°. Let dd be the new distance of the boat from the tower.

tan⁡(30°)=hd\tan(30°) = \frac{h}{d}

Since tan⁡(30°)=13\tan(30°) = \frac{1}{\sqrt{3}} (standard value):

13=603d\frac{1}{\sqrt{3}} = \frac{60\sqrt{3}}{d}

Solving for dd:

d=603×3d = 60\sqrt{3} \times \sqrt{3}

d=60×3d = 60 \times 3

d=180d = 180 metres


The boat was at 60 m, now it's at 180 m from the tower.

Distance traveled =180−60=120= 180 - 60 = 120 metres

Time taken =9= 9 seconds


Speed=DistanceTime\text{Speed} = \frac{\text{Distance}}{\text{Time}}

Speed=1209\text{Speed} = \frac{120}{9}

Speed=403\text{Speed} = \frac{40}{3} m/s


Converting to km/h by multiplying with 185\frac{18}{5} (since 11 m/s =3.6= 3.6 km/h):

Speed=403×185\text{Speed} = \frac{40}{3} \times \frac{18}{5}

Speed=40×183×5\text{Speed} = \frac{40 \times 18}{3 \times 5}

Speed=72015\text{Speed} = \frac{720}{15}

Speed=48\text{Speed} = 48 km/h


Therefore, the speed of the boat is 48 km/h.

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