A man is watching from the top of a tower a boat speeding away from the tower. The boat makes an angle of depression of 60° with the man's eye when at a distance of 60 metres from the tower. After 9 seconds, the angle of depression becomes 30°. The speed of the boat, assuming that it is running in still water, will be:
A man is watching from the top of a tower a boat speeding away from the tower. The boat makes an angle of depression of 60° with the man's eye when at a distance of 60 metres from the tower. After 9 seconds, the angle of depression becomes 30°. The speed of the boat, assuming that it is running in still water, will be:
Solution
A man at the top of a tower watches a boat speeding away. Initially, the boat is at a distance of 60 metres from the tower and makes an angle of depression of 60° with the man's eye. After 9 seconds, the angle of depression becomes 30°.
What we need to find: The speed of the boat
Understanding the setup: Imagine you're standing on top of a tower looking down at a boat. The boat is moving away from the tower in a straight line. "Angle of depression" is the angle you look downward from horizontal to see the boat.
When the boat is at the first position (60 m from the tower), the angle of depression is .
In a right triangle,
Since (standard value to memorize):
metres
After 9 seconds, the angle of depression becomes . Let be the new distance of the boat from the tower.
Since (standard value):
Solving for :
metres
The boat was at 60 m, now it's at 180 m from the tower.
Distance traveled metres
Time taken seconds
m/s
Converting to km/h by multiplying with (since m/s km/h):
km/h
Therefore, the speed of the boat is 48 km/h.
Related questions:
2026: 31 May Shift 1
2023: 21 May Shift 1