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A sum of money becomes ₹ 20070 after 3 year and ₹ 30105 after 6 years on compound interest. The sum will be

Solution

✅ Correct Option: 1

Given:

  • A sum becomes ₹20,070 after 3 years
  • The same sum becomes ₹30,105 after 6 years
  • Compound interest is applied

The time difference between the two amounts is exactly 3 years.


The amount at year 6 is the amount at year 3 grown for another 3 years.

Growth factor for 3 years =Amount at 6 yearsAmount at 3 years= \dfrac{\text{Amount at 6 years}}{\text{Amount at 3 years}}

Growth factor =30,10520,070= \dfrac{30,105}{20,070}

Growth factor =1.5= 1.5

The money grew 1.5 times in 3 years.


The principal also grows by a factor of 1.5 in 3 years to reach ₹20,070.

Principal ×1.5=20,070\times 1.5 = 20,070

Principal =20,0701.5= \dfrac{20,070}{1.5}

Principal =13,380= 13,380


Therefore, the original sum is ₹13,380.

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