If the 3rd of June, 2003 was a Tuesday, then what would be the day of the week on the 10th of June 2012?

The starting date is June 3, 2003, which is a Tuesday.

The target date is June 10, 2012.

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From June 3, 2003 to June 3, 2012 is exactly 9 years.

From June 3, 2012 to June 10, 2012 is 7 days.

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To find the total number of days in 9 years, we need to account for leap years.

Leap years between June 2003 and June 2012:

• 2004 (Feb 29, 2004 occurs after June 3, 2003)
• 2008 (Feb 29, 2008)
• 2012 (Feb 29, 2012 occurs before June 3, 2012)

Number of leap days = 3

Total days from June 3, 2003 to June 3, 2012:

$= 9 \times 365 + 3$

$= 3285 + 3$

$= 3288$ days

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Total days from June 3, 2003 to June 10, 2012:

$= 3288 + 7$

$= 3295$ days

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To find the day of the week, we find the remainder when dividing by 7:

$3295 = 470 \times 7 + 5$

This means 3295 days = 470 complete weeks + 5 days

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Starting from Tuesday and adding 5 days:

Tuesday → Wednesday → Thursday → Friday → Saturday → Sunday

Therefore, June 10, 2012 is a Sunday.

The answer is Option 1: Sunday.