A number when divided by 95 leaves a remainder 43. If the same number is divided by 19, then the remainder will be:

A number when divided by 95 leaves a remainder 43. The same number divided by 19 needs to be found.

If a number gives remainder 43 when divided by 95, it can be written as:

$N = 95k + 43$

where $k$ is the quotient.

---

Breaking down 95 and 43 using 19:

$95 = 19 \times 5$

$43 = 19 \times 2 + 5$

---

Substituting into the equation:

$N = 95k + 43$

$N = (19 \times 5)k + (19 \times 2 + 5)$

$N = 19 \times 5k + 19 \times 2 + 5$

$N = 19(5k + 2) + 5$

---

The final form shows:

$N = 19(5k + 2) + 5$

This means the number equals 19 times some integer, plus 5.

Therefore, when $N$ is divided by 19, the remainder is $5$.