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CUET General Test 2025 PYQs24 May Shift 2. Free, no login required.

Arithmetic

past year questions, CUET General Test 2025 24 May Shift 2

Percentages

past year questions, Arithmetic, CUET General Test 2025 24 May Shift 2

Easy

Match List-I with List-II

List-IList-II
(A) 17% of 1200(I) 198
(B) 18% of 1100(II) 204
(C) 19% of 1000(III) 200
(D) 40% of 500(IV) 190

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Calculate each percentage from List-I and match with the correct value in List-II.

Percentage of a number =Percentage100×Number= \frac{\text{Percentage}}{100} \times \text{Number}

(A) 17% of 1200

=17100×1200= \frac{17}{100} \times 1200

=17×12= 17 \times 12

=204= 204

(A) matches with (II)

(B) 18% of 1100

=18100×1100= \frac{18}{100} \times 1100

=18×11= 18 \times 11

=198= 198

(B) matches with (I)

(C) 19% of 1000

=19100×1000= \frac{19}{100} \times 1000

=19×10= 19 \times 10

=190= 190

(C) matches with (IV)

(D) 40% of 500

=40100×500= \frac{40}{100} \times 500

=25×500= \frac{2}{5} \times 500

=2×100= 2 \times 100

=200= 200

(D) matches with (III)

The correct matching is:

(A) - (II), (B) - (I), (C) - (IV), (D) - (III)

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