Match List-I with List-II
List-I List-II (A) Relationship between the variable input and output. (I) Average Product (B) Output per unit of variable input. (II) Marginal Product (C) Change in output per unit of change in the input (III) Law of variable proportions (D) The marginal product of a factor input initially rises with its employment level (IV) Total Product
Choose the correct answer from the options given below:
Match List-I with List-II
| List-I | List-II |
|---|---|
| (A) Relationship between the variable input and output. | (I) Average Product |
| (B) Output per unit of variable input. | (II) Marginal Product |
| (C) Change in output per unit of change in the input | (III) Law of variable proportions |
| (D) The marginal product of a factor input initially rises with its employment level | (IV) Total Product |
Choose the correct answer from the options given below:
Solution
(A) Relationship between the variable input and output → This describes Total Product (TP), which shows the entire relationship between input and output levels.
(B) Output per unit of variable input → This is the definition of Average Product (AP = Total Output / Variable Input).
(C) Change in output per unit of change in the input → This defines Marginal Product (MP = ΔOutput / ΔInput).
(D) The marginal product of a factor input initially rises with its employment level → This describes the Law of Variable Proportions, which explains the three stages of production where MP initially increases, reaches maximum, then decreases.
Hence, Option 1: (A) - (IV), (B) - (I), (C) - (II), (D) - (III) → Total Product represents the complete input-output relationship. Average Product measures productivity per unit of input. Marginal Product captures the rate of change in output. The Law of Variable Proportions explains the behavior of marginal product across different stages of production, stating that when more units of a variable input are combined with fixed inputs, the marginal product initially rises (Stage I), then falls but remains positive (Stage II), and eventually becomes negative (Stage III). → correct
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