Skip to main contentSkip to question navigationSkip to solution

IPMAT Rohtak 2019 (QA) PYQs

IPMAT Rohtak 2019

Number System
>
HCF & LCM

Conceptual

Find the HCF of 23,46,827\frac{2}{3}, \frac{4}{6}, \frac{8}{27}

Correct Option: 1
Firstly, we will simplify 46\frac{4}{6} which will become 23\frac{2}{3}. Hence, we are dealing with 2 unique fractions:
23,827\Rightarrow \frac{2}{3}, \frac{8}{27}
HCF of Fractions =HCF of the NumeratorsLCM of the Denominators=\frac{\text{HCF of the Numerators}}{\text{LCM of the Denominators}}
HCF of Numerators == HCF of 2,8=22, 8 = 2
LCM of Denominators == LCM of 3,27=273, 27 = 27
Hence, HCF of the fractions =227=\frac{2}{27}
Formula to remember:
HCF(xy,ab)=HCF(x,a)LCM(y,b)\text{HCF}\left( \dfrac{x}{y}, \dfrac{a}{b} \right) = \dfrac{\text{HCF}(x, a)}{\text{LCM}(y, b)}
LCM(xy,ab)=LCM(x,a)HCF(y,b)\text{LCM}\left( \dfrac{x}{y}, \dfrac{a}{b} \right) = \dfrac{\text{LCM}(x, a)}{\text{HCF}(y, b)}

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question