IPMAT Rohtak 2019 (QA) - Find the HCF of 2/3, 4/6, 8/27 | PYQs + Solutions

IPMAT Rohtak 2019

Number System

HCF & LCM

Conceptual

Find the HCF of $\frac{2}{3}, \frac{4}{6}, \frac{8}{27}$

\frac{2}{27}

\frac{8}{3}

\frac{2}{3}

\frac{8}{27}

✅ Correct Option: 1

Firstly, we will simplify

\frac{4}{6}

which will become

\frac{2}{3}

. Hence, we are dealing with 2 unique fractions:

\Rightarrow \frac{2}{3}, \frac{8}{27}

HCF of Fractions

=\frac{\text{HCF of the Numerators}}{\text{LCM of the Denominators}}

HCF of Numerators

=

HCF of

2, 8 = 2

LCM of Denominators

=

LCM of

3, 27 = 27

Hence, HCF of the fractions

=\frac{2}{27}

Formula to remember:

\text{HCF}\left( \dfrac{x}{y}, \dfrac{a}{b} \right) = \dfrac{\text{HCF}(x, a)}{\text{LCM}(y, b)}

\text{LCM}\left( \dfrac{x}{y}, \dfrac{a}{b} \right) = \dfrac{\text{LCM}(x, a)}{\text{HCF}(y, b)}