IPMAT Rohtak 2019Algebra > Easy442219None of the above✅ Correct Option: 1Related questions:The sum of the first 15 terms in an arithmetic progression is 200, while the sum of the next 15 terms is 350. Then the common difference isLet mn=902+5×90+4902+5×90+6×912+5×91+4912+5×91+6×.......×982+5×98+4982+5×98+6\dfrac{m}{n} = \dfrac{90^2+5 \times 90+4}{90^2+5\times 90+6} \times \dfrac{91^2+5\times 91+4}{91^2+5\times 91+6} \times .......\times \dfrac{98^2+5\times 98+4}{98^2+5\times 98+6}nm=902+5×90+6902+5×90+4×912+5×91+6912+5×91+4×.......×982+5×98+6982+5×98+4 where m and n are co-primes. What is the value of ∣m−n∣|m - n|∣m−n∣ ?Given (A=265)(A = 2^{65})(A=265) and (B=264+263+262+...+20)(B = 2^{64} + 2^{63} + 2^{62} + ... + 2^0)(B=264+263+262+...+20), which of the following is true?