Fruits were purchased for Rs 350. 9 boys ate $\frac{3}{5}$ of them in 2 hours. 6 boys feel their stomach as full so do not eat further. In how many hours the remaining fruits will get finished by remaining boys?

Given:

• 9 boys ate $\frac{3}{5}$ of fruits in 2 hours
  • Then 6 boys stop eating, leaving 3 boys
  • Remaining portion = $1 - \frac{3}{5} = \frac{2}{5}$ of fruits

Let's find the time $(t)$ needed for 3 boys to eat the remaining fruits:

Rate at which fruits are eaten:

• 9 boys eat $\frac{3}{5}$ in 2 hours
• 9 boys eat $\frac{3}{10}$ per hour

For remaining boys:

• 3 boys eat $\frac{3}{10} \times \frac{1}{3} = \frac{1}{10}$ per hour (Divided by 3 because there are 3 boys now)
• They need to eat $\frac{2}{5}$ portion

Time needed = $\frac{\text{portion to eat}}{\text{rate of eating}}$

$t = \frac{\frac{2}{5}}{\frac{1}{10}} = \frac{2}{5} \times \frac{10}{1} = 4$ hours

Therefore, it will take 4 hours for the remaining fruits to be finished.