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The number of four-digit integers which are greater than 1000 and divisible by both 2 and 3, but not by 5, is

Solution

Correct Option: 3

Number of items in an AP =lad+1= \dfrac{l-a}{d}+1, where:

l=l = last term

a=a = first term

d=d = common difference


Integers divisible by 22 and 33 \Rightarrow divisible by 66

Integers divisible by 61002,1008,,99966 \Rightarrow 1002,1008, \ldots ,9996

n1=999610026+1n_1= \frac{9996-1002}{6}+1

n1=1500n_1=1500


Integers divisible by 2,32,3 and 55 \Rightarrow divisible by 3030

Integers divisible by 301020,1050,,999030 \Rightarrow 1020,1050, \ldots, 9990

n2=9990102030+1n_2 = \frac{9990-1020}{30}+1

n2=300n_2=300


\therefore Total integers divisible by 22 and 33 but not 55:

=n1n2=1500300=1200=n_1-n_2=1500-300 = 1200

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