IPMAT Indore 2022Algebra > Easy{1}\{1\}{1}{1,−1}\{1,-1\}{1,−1}{1,0}\{1,0\}{1,0}{1,0,−1}\{1,0,-1\}{1,0,−1}✅ Correct Option: 2Related questions:The function f(x)=x3−5x2−8x3f(x) = \dfrac{x^3 - 5x^2 - 8x}{3}f(x)=3x3−5x2−8x isIf a function f(a)=max(a,0)f(a) = max (a, 0)f(a)=max(a,0) then the smallest integer value of xxx for which the equation f(x−3)+2f(x+1)=8f(x - 3) + 2f(x + 1) = 8f(x−3)+2f(x+1)=8 holds true is _______.Let fff and ggg be two functions defined by f(x)=∣x+∣x∣∣f(x) = |x + |x||f(x)=∣x+∣x∣∣ and g(x)=1xg(x) = \frac{1}{x}g(x)=x1 for x≠0x \neq 0x=0. If f(a)+g(f(a))=136f(a) + g(f(a)) = \frac{13}{6}f(a)+g(f(a))=613 for some real aaa, then the maximum possible value off(g(a)) f(g(a))f(g(a)) is: