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Is the answer 2?
No 1
Academic discussion and doubt solving for: HCF & LCM, Integral Solutions, Divisibility Rules, Factorisation, Unit Digit, Remainders.
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One number from a, a+2 and a+4 must be a multiple of 3. The only multiple of 3 which is a prime number is 3 itself, so one of them is 3. There is only one such triplet which satisfies the condition (3, 5 and 7).