Please log in to comment and participate in discussions.
Comments (2)
IPMAT/Number System
Academic discussion and doubt solving for: HCF & LCM, Integral Solutions, Divisibility Rules, Factorisation, Unit Digit, Remainders.
1319Members
82
Online
Members can post and comment here, and get these posts in their Latest feed.
Moderators
Join AfterBoards
Create an account to join our community and participate in discussions.
- • Connect with peers
- • Resolve doubts
- • Learn more about admissions

yeh point hi nahi samjha
Here is how i would do this question
Write the prime factorisation of each option
Take the biggest prime factor of each option and check the highest power that will suffice it for example
In option 1 we can see 11
Now we will
151/11+151/11² we will not take 11³ as it is greater than 131. 151/11 is not a division symbol it is checking how many 11's will suffice so 151/11 is 13 and 151/121 will be 1
13+1=14 I do not know why in the solution it is 13
For option 2 the max prime is again 11 so it will be the same
For option 3 it is 7 so 151/7+151/49 again 7³ is greater than 151 so won't take it
Similarly for option 4
We are checking that what is the highest power of the given option that will divide 151!
Above is the formula used
Shorter method
No need to manually check for each option
Just pick the highest prime from each option
Obviously 151! Will be divisible by a higher power of 7[i.e. contain more seven] as compared to 11.
So indirectly speaking we need to pick the option whose biggest prime factorization is the lowest among all the options
Highest prime factor of each option
A 11
B 11
C 7
D 13
Now the lowest among these is option C which is the answer
okay thank you!