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4x + 7y = 3
first find one solution:
mod 4 ⇒ 7y ≡ 3 ⇒ 3y ≡ 3 ⇒ y ≡ 1 (mod 4)
take y = 1 ⇒ 4x + 7 = 3 ⇒ x = -1
so general solution:
x = -1 + 7t
y = 1 - 4t
now apply constraints:
|x| < 100 ⇒ -100 < -1 + 7t < 100
⇒ -99 < 7t < 101
⇒ -14.14 < t < 14.42
⇒ t = -14 to 14
|y| < 100 ⇒ -100 < 1 - 4t < 100
⇒ -101 < -4t < 99
⇒ -24.75 < t < 25.25
⇒ t = -24 to 25
combine both:
t = -14 to 14
number of integer values:
= 14 - (-14) + 1 = 29
Academic discussion and doubt solving for: HCF & LCM, Integral Solutions, Divisibility Rules, Factorisation, Unit Digit, Remainders.
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is the ans 29?