here is the solution provided :
shouldn't the highlighted part be : 8(v-5) < n </= 8(v-4) ???
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Academic discussion and doubt solving for: HCF & LCM, Integral Solutions, Divisibility Rules, Factorisation, Unit Digit, Remainders.
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No, the highlighted part is correct.
“4 volunteers would not get anything” means chocolates are enough for only (v − 4) volunteers, not more.
So:
For (v − 4) volunteers → chocolates are enough
For (v − 3) volunteers → chocolates are not enough
That translates to:
8(v − 4) ≤ n < 8(v − 3)
Your version 8(v − 5) < n ≤ 8(v − 4) would mean chocolates are enough for (v − 4) but not even for (v − 4), which contradicts the condition.
So the original inequality is the correct one.
but when i asked the same question to gemini this is what its response was :
we don't know the number of chocolates the (v-4)th guy received -- it could be anywhere between 1-8. the least he could receive is 1 chocolate hence n > 8(v-5). and on the higher end he could receive exactly 8 chocolates which means n can be equal to or less than 8(v-4).
idk how am i interpreting it wrong :(