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•13d

angle AGB =90, bcs diameter subtends right angle at any point on the circumfernce of the circle. using pythagoras theorem, we get BG= 2root(5). in triangle ABC, using pythagoras we get (BC)^2= (4+GC)^2 - 36 ......(eq1), and in triangle BGC, we get (BC)^2= (GC)^2 + 20......(eq2). on solving these we get GC= 5 and therefore BC = root(45).

IPMAT/Geometry

Academic discussion and doubt solving for: Trigonometry, Straight Lines, Conic Sections, Circles, Triangles, Quadrilaterals, Solids, Polygons

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