could someone please tell me how to solve the 4th one
Please log in to comment and participate in discussions.
Unsure if this is the right thing but we learnt the CAGR formula in college:
CAGR=[(Final ValueInitial Value)1n−1]×100\text{CAGR} = \left[ \left( \frac{\text{Final Value}}{\text{Initial Value}} \right)^{\frac{1}{n}} - 1 \right] \times 100CAGR=[(Initial ValueFinal Value)n1−1]×100
CAGR=[(549.2180.4)14−1]×100≈[(3.04)0.25−1]×100≈32.0%\text{CAGR} = \left[ \left( \frac{549.2}{180.4} \right)^{\frac{1}{4}} - 1 \right] \times 100 \approx \left[ (3.04)^{0.25} - 1 \right] \times 100 \approx \mathbf{32.0\%}CAGR=[(180.4549.2)41−1]×100≈[(3.04)0.25−1]×100≈32.0%
Doing it manually:
We calculate the percentage increase for each year relative to the previous year:
Calculate the Average:
Average=47.8+28.0+16.4+38.24=130.44=32.6%\text{Average} = \frac{47.8 + 28.0 + 16.4 + 38.2}{4} = \frac{130.4}{4} = \mathbf{32.6\%}Average=447.8+28.0+16.4+38.2=4130.4=32.6%
yes its actually the 2nd one
thank you so much!
Academic discussion and doubt solving for: Tournaments, Arrangements, Puzzles, Bar Graphs, Tabular Data
Create an account to join our community and participate in discussions.
could someone please tell me how to solve the 4th one
Unsure if this is the right thing but we learnt the CAGR formula in college:
CAGR=[(Initial ValueFinal Value)n1−1]×100
CAGR=[(180.4549.2)41−1]×100≈[(3.04)0.25−1]×100≈32.0%
Doing it manually:
We calculate the percentage increase for each year relative to the previous year:
Calculate the Average:
Average=447.8+28.0+16.4+38.2=4130.4=32.6%
yes its actually the 2nd one
thank you so much!