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IPMAT/Arithmetic
Academic discussion and doubt solving for: Percentages, Ratios, Time & Work, Averages, Time/Speed/Distance, Mixture/Alligation, Profit/Loss, Simple/Compound Interest.
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hi there , you can solve using ratio , ratio of distance of A and B is 10:9 and that of B and C is 10:9 , so the final ratio of distance of A,B,C is 100(10x10) ; 90(9x10) : 81 (9:10 ) , the gap between A and C is 100-81 which is 19 , so 19 metres