is there is any other trick to do this question fast
this Sol is lengthy...
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idt the solution is lenghty.
for **maximum **value you take a as 1, b as -1 and c as 1 .
so eventually you get,
3+4+2+5+7=21
now for **minimum **we can't make everything negative ( as if we take a as -1, b as 1 and c as-1 then, as will become +1 and making 7 positive)
so in order to minimise the value we have to **either take a or c as +1 **.
( this will make 7 negative and then either 4 or 5 becomes positive)
We will take a as positive and c as negative as 4<5
it will make a=-1, b=1, c=-1
making it as, 3+4--2--5-7= -7
therefore the difference is 21-(-7)=28.
(mannn what is up with the bold text option!!)