Progression and series doubt

Can someone please explain this question..

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Comments (3)

Each term ai·ai+1 is either +1 or −1, so the sum is just n such terms. For the total to be 0, the number of +1 and −1 terms must be equal, so n must be even. Now if you multiply all terms, everything cancels nicely and you get a1²·a2²·…·an² = 1, which means the number of −1 terms must be even. Since the number of −1 terms is n/2, that must be even, so n is a multiple of 4.

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[p/synicdx](/forums/p/synicdx) bhaiya would you recommend watching JEE lectures (specifically chincholikar sir's) for progression and series? or just CAT lectures are sufficient to cover the concepts?

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S
sashiii
OP•7mos

But how do we know that on multiplying the terms it will be 1 only and not -1?

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