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BBA-DBE Bangalore 2026 PYQsQuantitative Ability. Free, no login required.

A polynomial P(x)=x4+3x3−5x2+7x+9P(x)=x^4+3x^3-5x^2+7x+9 is divided separately by (x−2)(x-2) and (x+1)(x+1), giving remainders R1R_1 and R2R_2, respectively. Find the value of R1+R22\dfrac{R_1+R_2}{2}.

Solution

✅ Correct Option: 1

By the Remainder Theorem, R1=P(2)R_1=P(2) and R2=P(−1)R_2=P(-1).

P(2)=16+24−20+14+9=43P(2)=16+24-20+14+9=43

P(−1)=1−3−5−7+9=−5P(-1)=1-3-5-7+9=-5

R1+R22=43−52=19\dfrac{R_1+R_2}{2}=\dfrac{43-5}{2}=19.

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