Skip to main contentSkip to solution

BBA-DBE Bangalore 2025 PYQsQuantitative Ability. Free, no login required.

In a flight of 1400 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 450 km/h and the time of flight increased by 60 minutes. The speed of the aircraft due to bad weather is what percent (rounded off to 2 decimal places) of the original speed of the aircraft?

Solution

✅ Correct Option: 1

Let the original speed be xx km/h

Reduced speed = (x−450)(x - 450) km/h

Distance = 14001400 km

Time increase = 6060 minutes = 11 hour


Using Time = Distance ÷ Speed:

Original time = 1400x\dfrac{1400}{x} hours

New time = 1400x−450\dfrac{1400}{x-450} hours


Since new time is 1 hour more than original time:

1400x−450−1400x=1\dfrac{1400}{x-450} - \dfrac{1400}{x} = 1


Multiplying by x(x−450)x(x-450):

1400x−1400(x−450)=x(x−450)1400x - 1400(x-450) = x(x-450)

1400x−1400x+630000=x2−450x1400x - 1400x + 630000 = x^2 - 450x

630000=x2−450x630000 = x^2 - 450x

x2−450x−630000=0x^2 - 450x - 630000 = 0


Using quadratic formula:

x=450±4502+4×6300002x = \dfrac{450 \pm \sqrt{450^2 + 4 \times 630000}}{2}

x=450±202500+25200002x = \dfrac{450 \pm \sqrt{202500 + 2520000}}{2}

x=450±27225002x = \dfrac{450 \pm \sqrt{2722500}}{2}

x=450±16502x = \dfrac{450 \pm 1650}{2}

Taking positive value: x=450+16502=1050x = \dfrac{450 + 1650}{2} = 1050 km/h


Reduced speed = 1050−450=6001050 - 450 = 600 km/h


Percentage = 6001050×100=57.14%\dfrac{600}{1050} \times 100 = 57.14\%

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question