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BBA-DBE Bangalore 2025 PYQsQuantitative Ability. Free, no login required.

In an election between two candidates, A and B, 18% of total voters did not cast their votes. 15% of the votes polled were declared invalid. B received 56% of the total valid votes and won by a majority of 6273 votes. The number of valid votes received by A was:

Solution

✅ Correct Option: 3

Let the total number of registered voters = VV


People who actually voted:

100%−18%=82%100\% - 18\% = 82\% of total voters

Votes polled = 0.82V0.82V


Valid votes from the polled votes:

100%−15%=85%100\% - 15\% = 85\% of polled votes

Valid votes = 0.85×0.82V=0.697V0.85 \times 0.82V = 0.697V


Votes received by each candidate:

B received 56%56\% of valid votes = 0.56×0.697V=0.39032V0.56 \times 0.697V = 0.39032V

A received remaining valid votes = 44%44\% of valid votes = 0.44×0.697V=0.30668V0.44 \times 0.697V = 0.30668V


Using the majority information:

B won by 62736273 votes, so:

0.39032V−0.30668V=62730.39032V - 0.30668V = 6273

0.08364V=62730.08364V = 6273

V=62730.08364=75000V = \dfrac{6273}{0.08364} = 75000


Valid votes received by A:

A's votes =0.30668×75000=23001= 0.30668 \times 75000 = 23001

Therefore, A received 2300123001 valid votes.

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