Q1:

2022: 30 Aug Shift 1

Trigonometry

Medium

Core

The value of sin⁡[2cot⁡−1(−512)]\sin\left[2\cot^{-1}\left(\frac{-5}{12}\right)\right] is :

Answer options
Option 2
Correct Answer
Explanation for 2022: 30 Aug Shift 1 MAT question 1

Q2:

2022: 16 July Shift 2

Trigonometry

Easy

Core

Match List I with List II

List I (Functions)List II (Principal value branches)
A. f(x)=cos⁡−1xf(x) = \cos^{-1} xI. [0,π][0, \pi]
B. f(x)=tan⁡−1xf(x) = \tan^{-1} xII. [0,π]−{π2}[0, \pi] - \left\{\frac{\pi}{2}\right\}
C. f(x)=cosec−1xf(x) = \text{cosec}^{-1} xIII. [−π2,π2]−{0}\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] - \{0\}
D. f(x)=sec⁡−1xf(x) = \sec^{-1} xIV. (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)

Choose the correct answer from the options given below:

Answer options

Q4:

2022: 16 July Shift 2

Trigonometry

Medium

Core

The value of cosec−1(−2)−2sec⁡−1(−2)\text{cosec}^{-1}(-2) - 2\sec^{-1}(-2) is equal to:

Answer options

Q5:

2022: 23 Aug Shift 1

Trigonometry

Medium

Core

sin⁡−1(cos⁡x)=π2−x\sin^{-1}(\cos x) = \frac{\pi}{2} - x is valid for :

Answer options
Option 2
Correct Answer
Explanation for 2022: 23 Aug Shift 1 MAT question 5

Q6:

2022: 25 May Shift 1

Trigonometry

Medium

Core

Match List I with List II

LIST ILIST II
A. sin⁡−1x+cos⁡−1x,x∈[−1,1]\sin^{-1} x + \cos^{-1} x, x \in [-1,1]I. −π2-\frac{\pi}{2}
B. tan⁡−13−cot⁡−1(−3)\tan^{-1} \sqrt{3} - \cot^{-1}(-\sqrt{3})II. −π6-\frac{\pi}{6}
C. cos⁡−1(cos⁡13π6)\cos^{-1}\left(\cos\frac{13\pi}{6}\right)III. π2\frac{\pi}{2}
D. sin⁡−1(−12)\sin^{-1}\left(-\frac{1}{2}\right)IV. π6\frac{\pi}{6}

Choose the correct answer from the options given below:

Answer options
Option 1
Correct Answer
Explanation for 2022: 25 May Shift 1 MAT question 6

Q7:

2022: 25 May Shift 1

Trigonometry

Easy

Core

Value of esin⁡(tan⁡−1x+cot⁡−1x)esin⁡(sin⁡−1x+cos⁡−1x),x∈[−1,1]\frac{e^{\sin(\tan^{-1} x + \cot^{-1} x)}}{e^{\sin(\sin^{-1} x + \cos^{-1} x)}}, x \in [-1, 1], is:

Answer options
Option 3
Correct Answer
Explanation for 2022: 25 May Shift 1 MAT question 7