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If the difference between the compound and simple interests on a certain sum of money for 2 years at 20% per annum is ₹ 64, then the sum in ₹ will be:

Solution

✅ Correct Option: 4

Let the principal be PP.

Time = 2 years

Rate = 20% per annum


Simple Interest formula: SI = P×R×T100\dfrac{P \times R \times T}{100}

SI =P×20×2100= \dfrac{P \times 20 \times 2}{100}

SI =40P100= \dfrac{40P}{100}

SI =0.4P= 0.4P


Compound Interest formula: CI = P×[(1+R100)n−1]P \times [(1 + \dfrac{R}{100})^n - 1]

CI =P×[(1+20100)2−1]= P \times [(1 + \dfrac{20}{100})^2 - 1]

CI =P×[(1.2)2−1]= P \times [(1.2)^2 - 1]

CI =P×[1.44−1]= P \times [1.44 - 1]

CI =0.44P= 0.44P


The difference between CI and SI is given as ₹64:

CI - SI =64= 64

0.44P−0.4P=640.44P - 0.4P = 64

0.04P=640.04P = 64

P=640.04P = \dfrac{64}{0.04}

P=64×25P = 64 \times 25

P=1600P = 1600

Therefore, the sum is ₹1600.

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