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A cashier has ₹ 620 in the denominations of two-rupee notes, ten-rupee notes and fifty-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he/she has ?

Solution

✅ Correct Option: 4

Let number of two-rupee notes, ten-rupee notes, and fifty-rupee notes be xx (since they're equal)

So, 2x+10x+50x=6202x+10x+50x=620

62x=62062x=620

x=10x=10

Hence, total number of notes would be 10+10+10=3010+10+10=30

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