IPMAT IndoreAlgebra > Mediumb1a1,b2a2,b3a3\dfrac{b_{1}}{a_{1}}, \dfrac{b_{2}}{a_{2}}, \dfrac{b_{3}}{a_{3}}a1b1,a2b2,a3b3 are in geometric progressionb1,b2,b3b_{1}, b_{2}, b_{3}b1,b2,b3 are in geometric progressionb1,b2,b3b_{1}, b_{2}, b_{3}b1,b2,b3 are in arithmetic progressionb1a1,b2a2,b3a3\dfrac{b_{1}}{a_{1}}, \dfrac{b_{2}}{a_{2}}, \dfrac{b_{3}}{a_{3}}a1b1,a2b2,a3b3 are in arithmetic progression✅ Correct Option: 4Related questions:IPMAT Indore 2022The 3rd ,14th 3^{\text {rd }}, 14^{\text {th }}3rd ,14th and 69th 69^{\text {th }}69th terms of an arithmetic progression form three distinct and consecutive terms of a geometric progression. If the next term of the geometric progression is the nth n^{\text {th }}nth term of the arithmetic progression, then nnn equals ________.IPMAT Indore 2021It is given that the sequence {xnx_nxn} satisfies x1=0,xn+1=xn+1+2√(1+xn)x_1 = 0, x_{n+1} = x_n + 1 + 2√(1+x_n)x1=0,xn+1=xn+1+2√(1+xn) for n=1,2,...n = 1,2,...n=1,2,... Then x31x_{31}x31 is _______IPMAT Indore 2019Assume that all positive integers are written down consecutively from left to right as in 1234567891011...... The 6389th digit in this sequence is