John's present age is one fourth of his father's age two years ago. John's father's age will be twice Raman's age after 10 years. If Raman's 12th birthday was celebrated 2 years ago, then what is John's present age?

Let John's present age be $x$ years

Given:

$x = \frac{1}{4}$ of father's age 2 years ago

Father's age after 10 years = 2 × Raman's age after 10 years

Raman's age now = $12 + 2 = 14$ years

Let's solve:

If John's father's age now is $y$ years

His age 2 years ago was $(y-2)$ years

Therefore: $x = \frac{y-2}{4}$ ... (1)

After 10 years:

Raman's age = $14 + 10 = 24$ years

Father's age = $y + 10$ years

Given: $y + 10 = 2 \times 24$

$y + 10 = 48$

$y = 38$ years

Substituting in equation (1):

$x = \frac{38-2}{4} = \frac{36}{4} = 9$

Therefore, John's present age is $9$ years.