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One-fifth of a number is equal to (58)th(\frac{5}{8})^{th} of another number. If 35 is added to the first number, it becomes four times the second number. Find the second number.

Solution

✅ Correct Option: 3

Let the first number be xx and second number be yy, then:

x5=5y8\frac{x}{5}=\frac{5y}{8}, x=25y8x=\frac{25y}{8}

and x+35=4yx+35=4y

which, we can rewrite as: 25y8+35=4y\frac{25y}{8}+35=4y

4y−25y8=354y-\frac{25y}{8}=35

7y8=35\frac{7y}{8}=35

y=40y=40

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