Algebra

Progression & Series

Easy

The sum of third and ninth term of an A.P is 8. Find the sum of the first 11 terms of the progression.

None of the above

✅ Correct Option: 1

Third term $=a+2d$

Ninth term $=a+8d$

According to the question,

$a+2d+a+8d=8$

$2a+10d=8$

We are asked to find sum of the first 11 terms.

$S_n=\frac{n}{2}[2a+(n-1)d]$

$S_{11}=\frac{11}{2}[2a+10d]=\frac{11}{2}[8]=44$

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The sum of third and ninth term of an A.P is 8. Find the sum of the first 11 terms of the progression.

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