10:[["$","title","0",{"children":"IPMAT Rohtak - A circle is inscribed in an equilateral triangle of side 24 cm, touching its sides. What is the area of the remaining portion of the triangle? | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined For an equilateral triang<= with inscribed circ<=: Side = a = 24 cm Area of equilateral triang<= = sqrt(3)4 a^2 = sqrt(3)4 24^2 = sqrt(3)4 576 = 144sqrt(3) cm^2 Radius of inscribed circ<= = asqrt(12) = 24sqrt(12) = 4sqrt(3) cm Area of inscribed circ<= = r^2 = (4sqrt(3))^2 = 48 cm^2 Remaining area = Area of triang<= - Area of circ<= = 144sqrt(3) - 48 cm^2 Therefore, the answer is 144sqrt(3) - 48 cm^2"}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"IPMAT Rohtak,QA,Geometry,Triangles"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"IPMAT Rohtak - A circle is inscribed in an equilateral triangle of side 24 cm, touching its sides. What is the area of the remaining portion of the triangle? | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined For an equilateral triang<= with inscribed circ<=: Side = a = 24 cm Area of equilateral triang<= = sqrt(3)4 a^2 = sqrt(3)4 24^2 = sqrt(3)4 576 = 144sqrt(3) cm^2 Radius of inscribed circ<= = asqrt(12) = 24sqrt(12) = 4sqrt(3) cm Area of inscribed circ<= = r^2 = (4sqrt(3))^2 = 48 cm^2 Remaining area = Area of triang<= - Area of circ<= = 144sqrt(3) - 48 cm^2 Therefore, the answer is 144sqrt(3) - 48 cm^2"}],["$","meta","9",{"property":"og:url","content":"https://www.afterboards.in/past-year-questions/ipmat-rohtak/2019/QA/31"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | IPMAT Rohtak Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"IPMAT Rohtak - A circle is inscribed in an equilateral triangle of side 24 cm, touching its sides. What is the area of the remaining portion of the triangle? | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined For an equilateral triang<= with inscribed circ<=: Side = a = 24 cm Area of equilateral triang<= = sqrt(3)4 a^2 = sqrt(3)4 24^2 = sqrt(3)4 576 = 144sqrt(3) cm^2 Radius of inscribed circ<= = asqrt(12) = 24sqrt(12) = 4sqrt(3) cm Area of inscribed circ<= = r^2 = (4sqrt(3))^2 = 48 cm^2 Remaining area = Area of triang<= - Area of circ<= = 144sqrt(3) - 48 cm^2 Therefore, the answer is 144sqrt(3) - 48 cm^2"}],["$","meta","17",{"name":"twitter:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","link","18",{"rel":"shortcut icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","19",{"rel":"icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","20",{"rel":"icon","href":"https://www.afterboards.in/icons/windows11/Square44x44Logo.altform-lightunplated_targetsize-256.png","sizes":"256x256","type":"image/png"}],["$","link","21",{"rel":"icon","href":"https://www.afterboards.in/icons/android/android-launchericon-512-512.png","sizes":"512x512","type":"image/png"}],"$L18","$L19","$L1a","$L1b","$L1c"]

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