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Based on the English alphabetical order, three of the following four letter cluster pairs are alike in a certain way and thus form a group. Which is the one that does not belong to that group?

Solution

✅ Correct Option: 4

The standard pattern followed by the group is:

  1. First →\rightarrow Second: Subtract 4
  2. Second →\rightarrow Third: Add 7
  3. Third →\rightarrow Fourth: Subtract 9
OptionLetter ClusterNumerical Values*Shift PatternConclusion
1GCJA7→3→10→17 \rightarrow 3 \rightarrow 10 \rightarrow 1−4, +7, −9-4, \ +7, \ -9Matches Group
2RNUL18→14→21→1218 \rightarrow 14 \rightarrow 21 \rightarrow 12−4, +7, −9-4, \ +7, \ -9Matches Group
3XTAR24→20→1→1824 \rightarrow 20 \rightarrow 1 \rightarrow 18−4, +7, −9-4, \ +7, \ -9Matches Group
4SOVB19→15→22→219 \rightarrow 15 \rightarrow 22 \rightarrow 2−4, +7, −20-4, \ +7, \ \mathbf{-20}Odd One Out

Note on Alphabet Math:

  • For XTAR: T(20)+7=27T(20) + 7 = 27, which wraps around the alphabet to start again at A(1).
  • Similarly, A(1 or 27)−9=18A(1 \text{ or } 27) - 9 = 18, which is R.

Why SOVB Failed

While the first two intervals of SOVB follow the rule (S→OS \to O is −4-4 and O→VO \to V is +7+7), the final step fails:

  • Expected: V(22)−9=13V (22) - 9 = 13 (Letter M)
  • Actual: V(22)→B(2)V (22) \rightarrow B (2)

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