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Based on the English alphabetical order, three of the following four are alike in a certain way and thus form a group. Which is the one that does not belong to that group?

Solution

✅ Correct Option: 4

We analyze the gap (interval) between the letters in each cluster using their alphabetical positions (A=1,B=2,…,Z=26A=1, B=2, \dots, Z=26).

The Common Pattern found in the first three groups:

  1. 1st to 2nd Letter: Subtract 5 (−5-5)
  2. 2nd to 3rd Letter: Add 11 (+11+11)
  3. 3rd to 4th Letter: Subtract 3 (−3-3)

Let's check each option against this pattern.

OptionClusterPositionsGap 1 (−5-5)Gap 2 (+11+11)Gap 3 (−3-3)Result
1WRCZ23,18,3,2623, 18, 3, 2623→1823 \to 18 (R)18→318 \to 3 (C)∗^*3→263 \to 26 (Z)∗∗^{**}Same
2SNYV19,14,25,2219, 14, 25, 2219→1419 \to 14 (N)14→2514 \to 25 (Y)25→2225 \to 22 (V)Same
3BWHE2,23,8,52, 23, 8, 52→232 \to 23 (W)∗∗^{**}23→823 \to 8 (H)∗^*8→58 \to 5 (E)Same
4GBNJ7,2,14,107, 2, 14, 107→27 \to 2 (B)2→142 \to 14 (N)14→1014 \to 10 (J)Different

Note on wrapping:

  • Gap 2 for WRCZ: 18+11=2918 + 11 = 29. Since alphabet has 26 letters, 29−26=329 - 26 = 3 (C).
  • Gap 1 for BWHE: 2−5=−32 - 5 = -3. Wrapping back from Z, 26−3=2326 - 3 = 23 (W).

The Error in GBNJ

  • Expected Pattern: B(2)+11B (2) + 11 should be M (13). Then M(13)−3M (13) - 3 should be J (10).
  • Actual Group: It uses N (14) instead of M. The gap used is +12+12 and −4-4.

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