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IPMAT Indore 2025 (SA) PYQs

IPMAT Indore 2025

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Tournaments

Easy

Eight teams take part in a tournament where each team plays against every other team exactly once. In a particular year, one team got suspended after playing 3 matches, due to a disciplinary issue. The organizers decide to proceed, nonetheless, with the remaining matches. The total number of matches that were played in the tournament that year is

Entered answer:

Correct Answer: 24
If a tournament has nn teams and they play against every other team once, the number of matches =n(n1)2=\boxed{\dfrac{n(n-1)}{2}}
Total matches with 8 teams =8×72=28= \dfrac{8 \times 7}{2} = 28 matches
When one team got suspended after playing 3 matches:
- 3 matches were already played involving the suspended team \newline - The suspended team would have played 7 other teams in total \newline - Since it played 3 matches before suspension, it missed playing 4 matches
Total matches played == Complete tournament matches - Matches not played due to suspension
Total matches played =284=24= 28 - 4 = 24

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