IPMAT Indore 2025 (SA) - Eight teams take part in a tournament where each team plays against every other team exactly once. In a particular year, one team got suspended after playing 3 matches, due to a disciplinary issue. The organizers decide to proceed, nonetheless, with the remaining matches. The total number of matches that were played in the tournament that year is | PYQs + Solutions

IPMAT Indore 2025

DILR

Tournaments

Easy

Eight teams take part in a tournament where each team plays against every other team exactly once. In a particular year, one team got suspended after playing 3 matches, due to a disciplinary issue. The organizers decide to proceed, nonetheless, with the remaining matches. The total number of matches that were played in the tournament that year is

Entered answer:

✅ Correct Answer: 24

In a tournament with

n

teams where each team plays against every other team once, the total number of matches is:

Total matches

=\dfrac{n(n-1)}{2}

With 8 teams:

Total matches

=\dfrac{8(8-1)}{2} = \dfrac{8 \times 7}{2} = 28

matches

When one team got suspended after playing 3 matches:

- 3 matches were already played involving the suspended team

\newline

- The suspended team would have played 7 other teams in total

\newline

- Since it played 3 matches before suspension, it missed playing 4 matches

Total matches played = Complete tournament matches - Matches not played due to suspension

Total matches played =

28 - 4 = 24