IPMAT Indore 2025Number System > EasyEntered answer:✅ Correct Answer: 11Related questions:The polynomial 4x10−x9+3x11−5x7+cx6+2x5−x4+x3−4x2+6x−24x ^ {10} - x ^ 9 + 3x ^ {11} - 5x ^ 7 + c x ^ 6 + 2x ^ 5 - x ^ 4 + x ^ 3 - 4x ^ 2 + 6x - 24x10−x9+3x11−5x7+cx6+2x5−x4+x3−4x2+6x−2 when divided by x−1x - 1x−1 leaves a remainder 2.2.2. Then the value of c+6c + 6c+6 isThe remainder when 111011+10111111^{1011} + 1011^{11}111011+101111 is divided by 999 isThe remainder when (2929)29(29^{29){29}}(2929)29 is divided by 999 is