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IPMAT Indore 2021 PYQsShort Answers (Quants). Free, no login required.

It is given that the sequence {xnx_n} satisfies x1=0,xn+1=xn+1+2√(1+xn)x_1 = 0, x_{n+1} = x_n + 1 + 2√(1+x_n) for n=1,2,...n = 1,2,... Then x31x_{31} is _______

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Solution

✅ Correct Answer: 960
Solution figure for IPMAT Indore 2021 SA question 3 (Algebra)

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