IPMAT Indore - It is given that the sequence x_n satisfies x_1 = 0, x_n+1 = x_n + 1 + 2√(1+x_n) for n = 1,2,... Then x_31 is _______ | PYQs + Solutions

IPMAT Indore

Algebra

Medium

Entered answer:

✅ Correct Answer: 960

Related questions:

IPMAT Indore 2019

Assume that all positive integers are written down consecutively from left to right as in 1234567891011...... The 6389th digit in this sequence is

IPMAT Indore 2022

The numbers $-16,2^{x+3}-2^{2 x-1}-16,2^{2 x-1}+16$ are in an arithmetic progression. Then $x$ equals ________.

IPMAT Indore 2025

Given that $1 + \frac{1}{2^2} + \frac{1}{3^2} + \frac{1}{4^2} + ... = \frac{\pi^2}{6}$ , the value of $1 + \frac{1}{3^2} + \frac{1}{5^2} + \frac{1}{7^2} + ...$ is

IPMAT Indore (SA) PYQs

Keyboard Shortcuts