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IPMAT Indore 2020 (MCQ) PYQs

IPMAT Indore 2020

Algebra
>
Progression & Series

Hard

If 112+122+132+\frac{1}{1^2} + \frac{1}{2^2} + \frac{1}{3^2} + \ldots up to =π26\infty = \frac{\pi^2}{6}, then the value of 112+132+152+\frac{1}{1^2} + \frac{1}{3^2} + \frac{1}{5^2} + \ldots up to \infty is

Correct Option: 1

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