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IPMAT Indore 2020 PYQsMultiple Choice (Quants). Free, no login required.

If 112+122+132+…\frac{1}{1^2} + \frac{1}{2^2} + \frac{1}{3^2} + \ldots up to ∞=π26\infty = \frac{\pi^2}{6}, then the value of 112+132+152+…\frac{1}{1^2} + \frac{1}{3^2} + \frac{1}{5^2} + \ldots up to ∞\infty is

Solution

✅ Correct Option: 1
Solution figure for IPMAT Indore 2020 MCQ question 5 (Algebra)

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