IPMAT Indore - ABCD is a quadrilateral whose diagonals AC and BD intersect at O. If triangles AOB and COD have areas 4 and 9 respectively, then the minimum area that ABCD can have is | PYQs + Solutions

IPMAT Indore

Geometry

Medium

✅ Correct Option: 2

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IPMAT Indore 2019

Points $P$ , $Q$ , $R$ , and $S$ are taken on sides $AB$ , $BC$ , $CD$ , and $DA$ of square $ABCD$ respectively, so that $\frac{AP}{PB} = \frac{BQ}{QC} = \frac{CR}{RD} = \frac{DS}{SA} = \frac{1}{n}$ . Then the ratio of the area of $PQRS$ to the area of $ABCD$ is

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Let $ABCD$ be a cyclic quadrilateral with $AB = 15, BC = 20, CD = 24$ and $AC = 25$ . Then $AD$ equals ___

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