9:{"metadata":[["$","title","0",{"children":"IIM-B (BBA-DBE) 2025 #1 - The perimeter of a rhombus is 148 cm and one of its diagonals is 70 cm. Its area is equal to the area of a trapezium whose parallel sides are x cm and 50 cm and the distance between the parallel sides is 14 cm. What is the value of x? | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined What we know: Perimeter = 148 cm A rhombus has 4 equal sides, so: Side <=ngth = 1484 = 37 cm

What we know: - One diagonal = 70 cm - Side <=ngth = 37 cm The diagonals of a rhombus cut each other at right ang<=s and split each other in half. This creates right-ang<=d triang<=s with: - One <=g = 702 = 35 cm - Other <=g = d_22 (unknown) - Hypotenuse = 37 cm Using Pythagoras theorem: 35^2 + (d_22)^2 = 37^2 1225 + (d_22)^2 = 1369 (d_22)^2 = 144 d_22 = 12 So d_2 = 24 cm

Area of rhombus = 12 d_1 d_2 Area = 12 70 24 = 840 cm²

For the trapezium: - Paral<=l sides are x cm and 50 cm - Height = 14 cm Area of trapezium = 12 (sum of paral<=l sides) height Area = 12 (x + 50) 14 = 7(x + 50)

Since both areas are equal: 840 = 7(x + 50) 8407 = x + 50 120 = x + 50 x = 70 cm"}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"IIM-B (BBA-DBE),QA,Geometry,Quadrilaterals"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"IIM-B (BBA-DBE) 2025 #1 - The perimeter of a rhombus is 148 cm and one of its diagonals is 70 cm. Its area is equal to the area of a trapezium whose parallel sides are x cm and 50 cm and the distance between the parallel sides is 14 cm. What is the value of x? | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined What we know: Perimeter = 148 cm A rhombus has 4 equal sides, so: Side <=ngth = 1484 = 37 cm

Area of rhombus = 12 d_1 d_2 Area = 12 70 24 = 840 cm²

For the trapezium: - Paral<=l sides are x cm and 50 cm - Height = 14 cm Area of trapezium = 12 (sum of paral<=l sides) height Area = 12 (x + 50) 14 = 7(x + 50)

Since both areas are equal: 840 = 7(x + 50) 8407 = x + 50 120 = x + 50 x = 70 cm"}],["$","meta","9",{"property":"og:url","content":"/past-year-questions/iimb-bbadbe/2025/slot-1/QA/15"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | IIM-B (BBA-DBE) 2025 #1 Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"IIM-B (BBA-DBE) 2025 #1 - The perimeter of a rhombus is 148 cm and one of its diagonals is 70 cm. Its area is equal to the area of a trapezium whose parallel sides are x cm and 50 cm and the distance between the parallel sides is 14 cm. What is the value of x? | PYQs + Solutions"}],"$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e","$L1f","$L20","$L21","$L22"],"error":null,"digest":"$undefined"}

IIM-B (BBA-DBE) 2025 #1 (QA) PYQs

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